20a^2-45=0

Solution for 20a^2-45=0 equation:

20a^2-45=0

a = 20; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·20·(-45)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*20}=\frac{-60}{40}
=-1+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*20}=\frac{60}{40}
=1+1/2
$